PETIN M.I.

PETIN - METON calendar

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`   Contents - http://Petin1Mikhail.narod.ru/index.htm          `
` `
`            XI. Example. The control of the calculating `
`                  `
`How does it calculate misalignments for:`
`- Day 1, Month 11, Year 2108  (5 October 2108 AD), `
`- Day 1, Month  2, Year 2198  (8 January 2198 AD) ?`
` `
`Is it the number of days that the new moon `
`comes after 12:00 of the first day of the month?`
` `
`Suppose, that the New Moon was on the Greenwich `
`meridian at noon (12.00) Day 01 Month 1, 1 AD, 1721436 JD `
`(or 11 January, 1 AD).`
`  This is an initial point of calculating.`
` `
`   In the PETIN-METON Calendar:`
`  Meton cycle(Simple)= 6940 days = 235 lunations = `
`                     = 19 solar(lunar) years.`
` `
`  Meton cycle(Leap) = 6939 days = 235 lunations = `
`                     = 19 solar(lunar) years.`
` `
`  2xMeton cycle(Simple)+ Meton cycle(Leap)=`
`             = 6940+6940+6939 = 20819 days = `
`          = 705 lunations = 57 solar(lunar) years. `
` `
`  5x[2xMeton cycle(Simple)+ Meton cycle(Leap)] + Meton cycle(Simple)= `
`       = 111035 days = 3760 lunations = 304 solar(lunar) years `
`See also Tables 1-6 and Examples IX-X `
`of Enclosure 3 - http://Petin46Mikhail.narod.ru/index.htm  .`
` `
`Then`
` `
`I.           Interval of time from Date 1 Month 1, 1 AD `
`   to Date 1 Month 11, 2108 AD equals:`
`2108-1=2107 lunar years and 10 lunar months.`
` `
`Further:`
`2107 = 6x304 + 4x57 + 1x38 + 17 years, where:`
` `
`6x304 years = 666210 days     or 22560 lunations `
`   4x 57       =  83276              2820`
`   1x 38(table 6)   =  13880               470`
`      17 (table 5) =   6172               209`
`----------------------------------------------`
`                 769538 days     or 26059 lunations  `
` `
`   It's necessary to add 10 lunar months = 5x(30+29)=295 days.`
` `
`II.       Finally interval of time from Date 1 Month 1, 1 AD (1721436 JD)`
`   to Date 1 Month 11, 2108 AD equals:`
`769538+295=769833 days (or `
`26059+10=26069 lunations).`
` `
`Further: 769833+1721436 = 2491269 JD`
`It is corresponds to the noon (12.00) 5 October 2108 AD`
`(Gregorian calendar).`
` `
`If the period of the Moon revolution equals 29.530588 days, `
`then 29,530588x26069=769832,90 days.`
`In this case the misalignment equals:`
`769832,90 – 769833 = -0,10 days.`
` `
`It is necessary to subtract this misalignment -0,10 days `
`from 12.00 5 October 2108 AD for defining the actual New Moon time, `
`which will be 09.34 5 October 2108 AD.`
` `
`III.   Analogically for Date 1 Month 2, 2198 AD.`
` `
`Interval of time from Date 1 Month 1, 1 AD to Date 1 Month 2,`
`2198 AD equals:`
`2198-1=2197 lunar years and 1 lunar month.`
` `
`2197 = 7x304 + 1x57 + 12 years, where:`
` `
`7x304 = 777245 days       or    26320 lunations`
`1x 57 =  20819                    705`
`   12 =   4341 (table 5)          147`
`-------------------------------------------`
`        802405 days       or    27172 lunations `
` `
` It's necessary to add 1 lunar month = 30 days (or 1 lunation). `
`    `
`Finally interval of time from Date 1 Month 1, 1 AD (1721436 JD) `
`to Date 1 Month 2, 2198 AD equals:`
`802405+30=802435 days (or `
`27172+1=27173 lunations).`
` `
`Further: 802435+1721436 = 2523871 JD `
`It is corresponds to the noon (12.00) 8 January 2198 AD,`
`2523871 JD (Gregorian calendar).`
` `
` The period of the Moon revolution equals 29.530588 days, `
`then 29,530588x27173=802434,67 days.`
`In this case the misalignment equals:`
`802434,67 – 802435 = -0,34 days.`
` `
`It is necessary to subtract this misalignment -0,34 days `
`from 12.00 8 January 2198 AD for defining the actual `
`New Moon time, which will be 03.44 8 January 2198 AD.`
` `

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